def insertion_sort(lst): for i in xrange(1,len(lst)): j = i while j > 0 and lst[j] < lst[j-1]: swap(lst, j, j-1) j -= 1 def insertion_sort2(lst): for i in xrange(1,len(lst)): val = lst[i] j = i-1 while j >= 0 and val < lst[j-1]: lst[j+1] = lst[j] j -= 1 lst[j+1] = val
Insertion sort provides best case $Ω(n)$ and worst case $O(n^2)$.
No comments:
Post a Comment